All posts by Manish Verma
Let AB and CD be identical rods joined at …
Take each side of the pyramid having resistance …
A point charge +q is brought near a solid isolated …
Chain of bicycle moves through two sprockets …
f(x) + f(y) + f(x)f(y) = 1For all values of $x,y \in R$f'(x) = ?
Putting y = x we have,
$2f(x) + {\left[ {f(x)} \right]^2} = 1$
$2f(x) + {\left[ {f(x)} \right]^2} + 1 = 1 + 1$
${[f(x) + 1]^2} = 2$
$f(x) = – 1 \pm \sqrt 2 $
Since f(x) is a constant function, $f'(x) = 0$.
