Two salts $A_2 X $ and MX have the same value of solubility product of $4.0 \times 10^ {-12} $. The ratio of their molar solubilities i.e. $\frac{{S({A_2}X)}}{{S(MX)}} =$ _ _ _ _ . (Round off to the nearest integer) Continue reading Two salts $A_2 X $ and MX have the same value of ….
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The molar solubility of $Zn(OH)_2 $ ….
The molar solubility of $Zn(OH)_2 $ in 0.1 M NaOH solution is $x \times 10^{-18} M$. The value of x is _ _ _ _ . (Nearest integer)
(Given: The solubility product of $Zn(OH)_2 $ is $2 \times 10^{-20} $)
Solution
$Zn{(OH)_2}\rightleftharpoons \mathop {Z{n^{2 + }}}\limits_s + 2\mathop {O{H^ – }}\limits_{2s + 0.1} $
${K_{sp}} = [Z{n^{2 + }}]{[O{H^ – }]^2} = s.{(2s + 0.1)^2}$
$\therefore 2 \times {10^{ – 20}} = s.{(2s + 0.1)^2} \approx {0.1^2} \times s$
$ \Rightarrow s = 2 \times {10^{ – 18}}$
$\therefore x = 2 $