Q: Why are most ships painted red below the waterline?
A: Ships are primarily painted below the waterline with anti-fouling paint to prevent marine growth. This paint traditionally contains cuprous oxide, which creates a natural red tint; the colour is a functional byproduct of the protection rather than a stylistic choice.
Assuming the existence of the compound shown that is given trivial name, “Ravana” what would you call it in IUPAC?
Hydrazine formed from Urea is further oxidised to $N_2$ as shown below:
$N{H_2} – \mathop {\mathop C\limits^\parallel }\limits^O – N{H_2} \xrightarrow[\text{Hoffmann Bromamide Degradation}]{\text{NaOBr}} N{H_2} – N{H_2} \longrightarrow {N_2}$
Assuming 1 dL of blood sample contains 30 mg of Urea, calculate the volume of $N_2$ gas obtained at NTP from the sample. Continue reading $N{H_2} – CO – N{H_2}\xrightarrow{NaOBr} {N_2}$
[18]-crown-6 has:
A) 18 Carbon & 6 Oxygen atoms
B) 6 Carbon & 18 Oxygen atoms
C) 12 Carbon & 6 Oxygen atoms
D) 6 Carbon & 12 Oxygen atoms
Key
Crown ether named [T]-crown-O, means T is the total number of atoms in the ring and O is the number of oxygen atoms in the ring.
For, [18]-crown-6 there are 6 Oxygen atoms and a total of 18 atoms.
So, number of Carbon atoms = 18 – 6 = 12
Hence, option (C).
The volume V of an enclosure contains a mixture of three gases, 16 g of oxygen, 28 g of nitrogen and 44 g of carbon dioxide at absolute temperature T. Consider R as universal gas constant. The pressure of the mixture of gases is :
(A) $\frac {3RT}{V}$ (B) $\frac {5}{2} \frac {RT}{V}$
(C) $\frac {88RT}{V}$ (D) $\frac {4RT}{V}$ Continue reading The volume V of an enclosure contains a mixture ….
A 6.50 molal solution of KOH (aq) has density of $1.89 g.cm^{-3} $. The molarity of solution is _ _ _ _ $mol.dm^{-3} $. (Round off to the nearest integer).
[Atomic masses: K = 39.0 u, O = 16.0 u, H = 1.0 u] Continue reading A 6.50 molal solution of KOH (aq) has density of $1.89 g.cm^{-3} $ ….
