Solution

Normally, resistive network problems are solved when steady-state is reached after the battery is connected. However, for this problem let us find equivalent resistance by transient-state analyses. Resistance is not affected whether it is steady-state or transient-state.

Let us place charge at point x alone. This charge will get distributed equally in four directions. Charge that flows towards y = .

Likewise, let us place charge – at point y alone. This charge will get distributed equally in four directions. Charge that flows towards x = – or charge that flows towards y = +.

When charge is placed at point x and charge – is placed at point y simultaneously, the charge that flows towards y = .

Also,

From (1) & (2), we have .

Now, try to do this problem in similar manner by taking alternate route xaby. You are welcome to share your solution via comment.

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