$f(5x) = \frac{{5x}}{{5x + 5}} = \frac{x}{{x + 1}}$

Given, $y = \frac{x}{{x + 5}}$

$\therefore y.x + 5y = x$

$ \Rightarrow x = \frac{{5y}}{{1 – y}}$

Now, $f(5x) = \frac{x}{{x + 1}} = \frac{{\frac{{5y}}{{1 – y}}}}{{\frac{{5y}}{{1 – y}} + 1}}$

$ = \frac{{5y}}{{4y + 1}} = g(y)$