Assuming $\beta > \alpha $ which of the following option(s) is/are correct?

(A) $y \le \alpha $
(B) $y \ge \beta $
(C) $\alpha \le y \le \beta $
(D) $y \in \mathbb{R}$ Continue reading $y = \frac{{{x^2} – \alpha \beta }}{{2x – \alpha – \beta }}$

$x \in \mathbb{R} – \left\{ {\frac{{\alpha + \beta }}{2}} \right\}$

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