The pressure acting on a submarine is 3×105Pa at a certain depth. If the depth is doubled, the percentage increase in the pressure acting on the submarine would be:
(Assume that atmospheric pressure is 1×105Pa, density of water is 103kgm−3, g=10ms−2)
(A) 3200%
(B) 5200%
(C) 2003%
(D) 2005% Continue reading The pressure acting on a submarine is 3×105Pa ….
A plane electromagnetic wave of frequency 500 MHz is travelling in vacuum along y-direction. At a particular point in space and time, →B=8.0×10−8ˆzT. The value of electric field at this point is:
(speed of light = 3×108ms−1)
ˆx,ˆy,ˆz are unit vectors along x, y and z directions.
(A) 24ˆxV/m
(B) 2.6ˆxV/m
(C) −24ˆxV/m
(D) −2.6ˆyV/m Continue reading A plane electromagnetic wave of frequency 500 MHz ….
A fringe width of 6 mm was produced for two slits separated by 1 mm apart. The screen is placed 10 m away. The wavelength of light used is ‘x’ nm. The value of ‘x’ to the nearest integer is _ _ _ _ . Continue reading A fringe width of 6 mm was produced ….
For an electromagnetic wave traveling in free space, the relation between average energy densities due to electric (Ue) and magnetic (Um) fields is:
(A) Ue>Um
(B) Ue=Um
(C) Ue≠Um
(D) Ue<Um Continue reading For an electromagnetic wave traveling in free space ….
The maximum and minimum distances of a comet from the Sun are 1.6×1012 m and 8.0×1010 m respectively. If the speed of the comet at the nearest point is 6×104 m/s, the speed at the farthest point is:
(A) 3.0×103 m/s
(B) 1.5×103 m/s
(C) 4.5×103 m/s
(D) 6.0×103 m/s Continue reading The maximum and minimum distances of a comet ….
A sinusoidal voltage of peak value 250 V is applied to a series LCR circuit, in which R=8Ω, L=24mH and C=60μF. The value of power dissipated at resonant condition is ‘x’ kW. The value of x to the nearest integer is _ _ _ _ . Continue reading A sinusoidal voltage of peak value 250 V ….
The resistance R=VI, where V=(50±2)V and I=(20±0.2)A. The percentage error in R is ‘x’ %. The value of ‘x’ to the nearest integer is _ _ _ _ . Continue reading R=VI
V=(50±2)V
I=(20±0.2)A
% Error = ?
