Tag Archives: JEE Mains

Let a vector $\alpha \hat i + \beta \hat j $ be obtained by ….

Let a vector $\alpha \hat i + \beta \hat j $ be obtained by rotating the vector $\sqrt 3 \hat i + \hat j $ by an angle $45^\circ $ about the origin in counterclockwise direction in the first quadrant. Then the area of triangle having vertices $(\alpha , \beta )$, $(0, \beta )$ and (0, 0) is equal to:

(A) $2\sqrt 2 $
(B) $\frac {1}{2}$
(C) 1
(D) $\frac {1}{\sqrt 2 }$ Continue reading Let a vector $\alpha \hat i + \beta \hat j $ be obtained by ….

$\frac {dy}{dx} + 2y tan x = sin x $

$y (\frac {\pi}{3})=0$

${y_{\max }} = ?$

If y = y(x) is the solution to the differential equation, $\frac {dy}{dx} + 2y tan x = sin x $, $y (\frac {\pi}{3})=0$, then the maximum value of the function y(x) over R is equal to:

(A) $\frac {1}{2} $
(B) $\frac {1}{8} $
(C) $-\frac {15}{4}$
(D) 8 Continue reading $\frac {dy}{dx} + 2y tan x = sin x $

$y (\frac {\pi}{3})=0$

${y_{\max }} = ?$