IIT JEE $I(x) = \int {{{\left( {\frac{{{{\sin }^2}x}}{{{{\cos }^{14}}x}}} \right)}^{1/3}}dx} $ January 10, 2023 Engineer Manish Verma Leave a comment Solution [.pdf] Share this: Click to share on X (Opens in new window) X Click to share on Facebook (Opens in new window) Facebook Related