IIT JEE $\frac{{{x^4} – {x^2}}}{{{x^6} + 2{x^3} – 1}}$ September 24, 2023 Engineer Manish Verma Leave a comment $\begin{array}{l}y = \frac{{{x^4} – {x^2}}}{{{x^6} + 2{x^3} – 1}},x > 1\\{y_{\max }} = ?\end{array}$ Solution [.pdf] Share this:Click to share on Twitter (Opens in new window)Click to share on Facebook (Opens in new window) Related
