An empty LPG cylinder weighs 14.8 kg. When full, it weighs 29.0 kg and shows a pressure of 3.47 atm. In the course of use at ambient temperature, the mass of the cylinder is reduced to 23.0 kg. The final pressure inside the cylinder is _ _ _ _ atm. (Nearest integer)
(Assume LPG to be an ideal gas)

Solution

Weight of gas before use = 29.0 – 14.8 = 14.2 kg

Weight of gas after use = 23.0 – 14.8 = 8.2 kg

Now, $\frac {P_1}{n_1} = \frac {P_2}{n_2} $

$\Rightarrow \frac {P_1}{w_1} = \frac {P_2}{w_2} $

$\therefore \frac {3.47}{14.2} =  \frac {P_2}{8.2} $

$\Rightarrow P_2 = \frac {3.47 \times 8.2}{14.2} \approx 2 atm $

Answer: 2