Category Archives: Physics

An electromagnetic wave of wavelength $’\lambda ‘$ ….

An electromagnetic wave of wavelength $’\lambda ‘$ is incident on a photosensitive surface of negligible work function. If ‘m’ mass of photoelectron emitted from the surface has de-Broglie wavelength $\lambda_d$, then:

(1) $\lambda  = \left( {\frac{{2m}}{{hc}}} \right){\lambda _d}^2$
(2) ${\lambda _d} = \left( {\frac{{2mc}}{h}} \right){\lambda ^2}$
(3) $\lambda  = \left( {\frac{{2mc}}{h}} \right){\lambda _d}^2$
(4) $\lambda  = \left( {\frac{{2h}}{{mc}}} \right){\lambda _d}^2$ Continue reading An electromagnetic wave of wavelength $’\lambda ‘$ ….

A cup of coffee cools from $90^{\circ}$C ….

A cup of coffee cools from $90^{\circ}$C to $80^{\circ}$C in t minutes when the room temperature is $20^{\circ}$C. The time taken by a similar cup of coffee to cool from $80^{\circ}$C to $60^{\circ}$C at the same room temperature $20^{\circ}$C is:

(1) $\frac {13}{10}$t
(2) $\frac {13}{5}$t
(3) $\frac {10}{13}$t
(4) $\frac {5}{13}$t Continue reading A cup of coffee cools from $90^{\circ}$C ….

A particle moving in a circle of radius R ….

A particle moving in a circle of radius R with a uniform speed takes time T to complete one revolution. If this particle were projected with the same speed at an angle ‘$\theta $’ to the horizontal, the maximum height attained by it equals 4R. The angle of projection ‘$\theta $’ is then given by:

(1) $\theta  = {\cos ^{ – 1}}\sqrt {\frac{{g{T^2}}}{{{\pi ^2}R}}} $
(2) $\theta  = {\cos ^{ – 1}}\sqrt {\frac{{{\pi ^2}R}}{{g{T^2}}}} $
(3) $\theta  = {\sin ^{ – 1}}\sqrt {\frac{{{\pi ^2}R}}{{g{T^2}}}} $
(4) $\theta  = {\sin ^{ – 1}}\sqrt {\frac{{2g{T^2}}}{{{\pi ^2}R}}} $ Continue reading A particle moving in a circle of radius R ….