123IITJEE

123IITJEE

Skip to content

Admission
LIVE 1:1 Classes
Study Material
LIVE & Recorded Classes
Recorded Classes
- XI/XII/XII-Pass
- Foundation
Test Series
- XI/XII/XII-Pass
- Foundation
Results & Testimonials
Access Courses
Contact

Search for:

Physics

A non-conducting ring of radius 0.5 m……..

November 26, 2014 Engineer Manish Verma Leave a comment

Share this:

Click to share on Twitter (Opens in new window)
Click to share on Facebook (Opens in new window)

Related

Electric Field Potential

Post navigation

Previous Post\(\int {\frac{{sinx}}{{cos3x}} + \frac{{sin3x}}{{cos9x}} + \frac{{sin9x}}{{cos27x}}dx} \)Next PostDo capacitors in series always have same charge…….

Leave a ReplyCancel reply

Physics, Math etc. by IIT Alumnus Online and Bhopal

Admission
LIVE 1:1 Classes
Study Material
LIVE & Recorded Classes
Recorded Classes
- XI/XII/XII-Pass
- Foundation
Test Series
- XI/XII/XII-Pass
- Foundation
Results & Testimonials
Access Courses
Contact

Blog Posts

${\scriptscriptstyle 6 + f(x) = 2f( – x) + 3{x^2}\int\limits_{ – 1}^1 {f(t)dt}}$
$\scriptstyle f(x) = {\left( {\frac{x}{\pi }} \right)^x} + {\left( {\frac{\pi }{x}} \right)^x}$
$\scriptstyle \sqrt {7 – \sqrt {7 + \sqrt {7 – \sqrt {7 + …..} } } }$
$\scriptstyle f(x) = \int\limits_0^x {{\pi ^t}(t – e)(t – \pi )dt} $
$\scriptstyle 7f(x) + 5f\left( {\frac{1}{x}} \right) = x + 1$ …

Search for:

Open Lectures

Lectures for IIT-JEE
Lectures for Foundation IX/X

Subscribe to Posts via Email

Email Address

Join 5,644 other subscribers

Sound Engineering

JEE Main & Advanced Preparation Online / India (Bhopal)

All rights reserved. 123IITJEE, Where Technology Meets Quality Education!

Powered by https://manishverma.site