Math If $x+\frac {1}{x}=2,x\neq 0$$x^{99}+\frac {1}{x^{99}}=?$ June 18, 2023 Engineer Manish Verma Leave a comment We have, $x^2+1-2x=0$ $\Rightarrow (x-1)^2=0$ $\Rightarrow x=1$ $\therefore x^{99}+\frac {1}{x^{99}}=1+1=2$ Share this:Click to share on Twitter (Opens in new window)Click to share on Facebook (Opens in new window) Related
