IIT JEE ${y_1} = 10\sin \left( {3\pi t + \frac{\pi }{4}} \right)$ & ${y_2} = 5\left[ {\sin (3\pi t) + \sqrt 3 \cos (3\pi t)} \right]$ November 3, 2022 Engineer Manish Verma Solution [.pdf] Share this: Click to share on X (Opens in new window) X Click to share on Facebook (Opens in new window) Facebook Related