In the case of point charge like q, the equipotential surface is spherical. This means that,
$V_B = V_C $
So, $W_{AB} = W_{AC}$
Since A is closer to q than B is, $V_A \neq V_B$
So, $W_{AB} \neq 0 $
Hence, (C)
In the case of point charge like q, the equipotential surface is spherical. This means that,
$V_B = V_C $
So, $W_{AB} = W_{AC}$
Since A is closer to q than B is, $V_A \neq V_B$
So, $W_{AB} \neq 0 $
Hence, (C)