IIT JEE $\Delta = \left| {\begin{array}{*{20}{c}}1&{\cos (\beta – \alpha )}&{\cos (\gamma – \alpha )}\\{\cos (\alpha – \beta )}&1&{\cos (\gamma – \beta )}\\{\cos (\alpha – \gamma )}&{\cos (\beta – \gamma )}&1\end{array}} \right|$ December 17, 2022 Engineer Manish Verma Solution [.pdf] Share this:Click to share on Twitter (Opens in new window)Click to share on Facebook (Opens in new window) Related