Math f(x) + f(y) + f(x)f(y) = 1For all values of x,y∈Rf'(x) = ? November 1, 2023 Manish Verma Leave a comment Putting y = x we have, 2f(x)+[f(x)]2=1 2f(x)+[f(x)]2+1=1+1 [f(x)+1]2=2 f(x)=–1±√2 Since f(x) is a constant function, f′(x)=0. Share this: Click to share on X (Opens in new window) X Click to share on Facebook (Opens in new window) Facebook Related