A particle moving in a circle of radius R with a uniform speed takes time T to complete one revolution. If this particle were projected with the same speed at an angle ‘$\theta$’ to the horizontal, the maximum height attained by it equals 4R. The angle of projection ‘$\theta$’ is then given by:

(1) $\theta  = {\cos ^{ – 1}}\sqrt {\frac{{g{T^2}}}{{{\pi ^2}R}}}$
(2) $\theta  = {\cos ^{ – 1}}\sqrt {\frac{{{\pi ^2}R}}{{g{T^2}}}}$
(3) $\theta  = {\sin ^{ – 1}}\sqrt {\frac{{{\pi ^2}R}}{{g{T^2}}}}$
(4) $\theta  = {\sin ^{ – 1}}\sqrt {\frac{{2g{T^2}}}{{{\pi ^2}R}}}$ Continue reading A particle moving in a circle of radius R …. →