A fringe width of 6 mm was produced for two slits separated by 1 mm apart. The screen is placed 10 m away. The wavelength of light used is ‘x’ nm. The value of ‘x’ to the nearest integer is _ _ _ _ . Continue reading A fringe width of 6 mm was produced ….
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The width of one of the two slits in a YDSE ….
The width of one of the two slits in a Young’s double slit experiment is three times the other slit. If the amplitude of light coming from a slit is proportional to the slit-width, the ratio of minimum to maximum intensity in the interference pattern is x:4 where x is _ _ _ _ .
Solution
Given, $\frac {A_1}{A_2} = \frac {3}{1} $
Now, $\frac {I_1}{I_2} = \frac {A_1 ^2 }{A_2 ^2} = (\frac {3}{1})^2 = \frac {9}{1} $
$\frac {I_{min}}{I_{max}} = \frac {(\sqrt I_1 – \sqrt I_2 )^2 }{(\sqrt I_1 + \sqrt I_2 )^2} = \frac {(3-1)^2}{(3+1)^2}=1:4 $
Answer: 1.00
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