When light of wavelength 248 nm falls on a metal of threshold energy 3.0 eV, the de-Broglie wavelength of emitted electron is _ _ _ _ $A^\circ $. (Round off to the nearest integer)
[Use $\sqrt 3 = 1.73$, $h=6.63 \times 10^{-34} Js$, $m_e = 9.1 \times 10^{-31} Kg $, $c = 3.0 \times 10^8 ms^{-1}$, $1 eV = 1.6 \times 10^{-19} J$] Continue reading When light of wavelength 248 nm falls on a metal ….